11.01 scientific theory of Gases
The relation for temperature of a gas is given by:
(A) 12KT12KT
(C) 23KT23KT
(D) 32KT32KT
A device primarily based upon the physical science property
of matter is called:
Heat is kind of:
According to Charles law:
(A) V∝TV∝T
(B) V∝nV∝n
(C) P∝1TP∝1T
(D) P∝1VP∝1V
The ideal gas law is:
The SI unit of product of pressure and volume is:
The value of Boltzman’s constant is:
(A) 1.38×10−23JK1.38×10−23JK
(B) 1.38×1023JK1.38×1023JK
(C) 1.38×10−23Jmol.K1.38×10−23Jmol.K
(D) 1.38×1023Jmol.K1.38×1023Jmol.K
At constant temperature, if pressure of a given mass of gas
is halved, then its volume becomes:
S.I unit of pressure of gas is:
(A) Nm−2Nm−2
(B) N.mN.m
(C) N2mN2m
(D) N2mN2m
For gas, the P.E. related to its molecules is:
(C) 12kx2012kx02
(D) 12kx012kx0
At constant temperature and pressure, if volume of given
mass of a gas is doubled then:
(B) 1414 of original
(C) 1212 of original
Temperature of a gas is redoubled from 27oC to 127oC. The
quantitative relation of its mean K.E will be:
Boltzman constant, universal universal gas constant
Avogadro's number ar referred to as as:
(A) K=RNAK=RNA
(B) K=NAKK=NAK
(C) R=KNAR=KNA
(D) R=NAKR=NAK
Boltzman constant “k” has same unit as:
(A) Temperature
(B) Energy
(C) Entropy
(D) Perssure
If the temperature of a gas is constant then
<12mv2><12mv2> of the molecules of gas can be:
(A) Constant
(B) Zero
(C) Increase
(D) Decrease
The mean K.E. of gas
is at :
(A) 0 oC
(B) -273 oC
(C) 100 K
(D) 100 oC
The ideal gas law is given within the form:
(A) PV=nR/T
(B) PT=NRV
(C) PV=nRT
(D) TV=nRP
The average change of location K.E. of a molecule of a gas
at temperature T is proportional to:
(C) T−−√T
(D) T2
The unit of pressure of gas is:
(A) 1 Nm-2
(B) One Pascal
(C) One atmosphere
(D) All of the higher than
At constant temperature, if the quantity of the given mass
of gas is doubled, then the density of gas becomes:
(A) Double
(B) 1/4 of the initial worth
(C) 1/2 of the initial worth
(D) Remains constant
General gas law or general gas equation comes from:
(A) Boyle’s law
(B) Charle’s law
(C) Avogadro’s law
(D) All of the higher than
Solid ice, Liquid water and water vapours consist in
equilibrium at a temperature:
(A) 273 K
(B) 273.16 K
(C) 273o C
(D) 100o C
11.02 Internal Energy
The internal energy of a bit of lead once crushed by hammer
will:
At that of the subsequent temperature, a body has most
internal energy:
(A) −273oC−273oC
(B) 0K0K
In physical science system internal energy decreases by 100J
and 100J of labor done on the system then heat lost can be:
A substance gas molecules has:
(A) Temperature
(B) Pressure
(C) Path
(D) Final and initial state
The add of all the energies of molecules is understood as:
(A) Elastic P.E.
(B) K.E.
(C) Internal energy
(D) attraction P.E.
Average translation K.E of a gas molecule is:
(A) 12KT12KT
(C) 23KT23KT
(D) 32KT32KT
11.03 Work and warmth
The value of molar universal gas constant ‘R’ in SI units
is:
(A) 83.10 J mol-1 K-1
(B) 0.83 J mol-1 K-1
(C) 8.89 J mol-1 K-1
(D) 8.31 J mol-1 K-1
If P = Pressure ; V = Volume of a gas PΔVPΔV represents:
(A) Work
(B) Density
(C) Power
(D) Temperature
11.04 initial Law of physical science
The first law of physical science for associate equal method
is:
First Law of physical science for associate activity are
going to be written as:
(A) Q = W
(B) Q = -W
(C) W=−ΔUW=−ΔU
(D) W=ΔUW=ΔU
In case of activity first law of physical science is written
as:
(A) W=ΔuW=Δu
(B) W = Q
(C) W=Q−ΔuW=Q−Δu
(D) W=−ΔuW=−Δu
If the temperature of a system is unbroken constant, the
method is named.
(A) activity
(B) Isochoric method
(C) equal method
(D) Isobaric method
Which remains constant in associate adiabatic process?
(A) Volume
(B) Pressure
(C) Entropy
Cloud formation in atmosphere is associate example of:
(A) equal method
(C) activity
Entropy remains constant in:
(A) equal method
(C) Isochoric method
The modification in internal energy is outlined as:
(A) Q - W
The work worn out isochoric method is:
(A) Constant
(B) Variable
(C) Zero
(D) depend on condition
In thermodynanicsprocess, the equqtion W=−ΔUW=−ΔU
reprersents.
(A) equal expension
(B) equal compression
(C) adiabatic expension
(D)Adiabatic compression
A system will 700 Joules of labor and at an equivalent time
its internal energy will increase to four hundred Joules, heat provided by the
supply is:
(A) 700 Joules
(B) four hundred Joules
(C) 1100 Joules
(D) three hundred Joules
If internal energy decreases by three hundred J and a
hundred and twenty J of labor is finished on the system then heat can be:
(A) 420 J
(B) 320 J
(C) 400 J
(D) 300 J
If TH = T1 = 327o and metallic element = T2 = twenty seven
Co, then potency can be:
(A) 50 %
(B) 52 %
(C) 100 %
(D) Zero
11.05 Molar Specific Heats of a Gas
The distinction between Cp and Cv is equal to:
(A) Plank's constant
For a matter gas Cv = 5R25R2 then gamma for this gas is:
(A) 5757
(B) 435435
(C) 7575
(D) 354354
A gas that strictly obeys the gas law below all conditions
of temperature and pressure is called:
(A) Real gas
(B) gas
(C) Permanent gas
(D) chemical element
The ideal gas equation PV = RT holds sensible for:
(A) Any volume of the gas
(B) One metric capacity unit of gas
(C) One metric weight unit of gas
(D) One mole of the gas
The amount of warmth needed to lift the temperature of 1
mole of a substance through 1o K is called:
(A) heat energy
(B) Heat capability
(C) Heat of fusion
(D) Molar heat energy
The temperature of a system remains constant in:
(A) action
(B) Isobaric method
(C) equal method
(D) action
11.06 Reversible and Irreversible Processes
Which is associate example of irreversible process?
11.07 engine
Number of spark plugs required within the ICE are:
The potency of ICE is about:
(A) twenty five you have to half-hour
(B) thirty five you have to forty nada
(C) forty you have to fifty nada
(D) fifty you have to hour
For operating of warmth engine, there should be:
(A) a supply
(B) a sink
(C) either of those
(D) each of those
A system during which there's no transfer of mass and energy
across the boundary is called:
(A) associate open system
(B) A closed system
(C) associate isolated system
(D) an ideal system
The highest potency of a engine whose lower temperature is
17o C and extreme temperature of 200o C is:
(A) 70 %
(B) 100 %
(C) 35 %
(D) 38 %
11.09 Carnot|Nicolas Leonard Sadi Carnot|physicist} Engine
and Carnot s Theorem
The potency of warmth engine whose sink is at 17OC and
supply at 200OC is:
(A) 38%
(B) 65%
(C) 80%
(D) 90%
An ideal reversible engine has:
(A) 100% potency
(B) 80%
An ideal engine will solely be 100% economical if its cold
temperature reservoir is at:
(A) 0 K
(B) 0oC0oC
(D) 100oC100oC
The heat energy of fusion of ice is:
(A) 3.36×105JK−13.36×105JK−1
(B) 3.36×106JK−13.36×106JK−1
(C) 3.36×107JK−13.36×107JK−1
(D) 3.36×108JK−13.36×108JK−1
The potency of a Carnot engine is 100% if temperature of sink T2 is:
(A) 0oC0oC
(C) 0oF0oF
A Carnot engine has associate potency of fifty once its sink
temperature is at 27oC. The temperature of source:
(A) 273oC273oC
(B) 300oC300oC
(C) 327oC327oC
(D) 373oC373oC
If engine absorbs four hundred J and rejects two hundred J
energy, its potency can be:
(A) 100%
(B) 50%
(C) Zero
(D) infinite
Efficiency of a engine operating between twenty seven oC and
327 oC can be:
(A) 50 %
(B) 90 %
(C) 40 %
(D) 61 %
The potency of a Carnot engine operating between higher and
lower temperature T1 and T2 severally is given by:
(A) η=T2−T1T1η=T2−T1T1
(B) η=T1−T2T1η=T1−T2T1
(C) η=T2T1−T2η=T2T1−T2
(D) η=T1T1−T2η=T1T1−T2
The potency of a Carnot engine is:
(A) Infinite
(B) Zero
(C) but one
(D) bigger than one